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How to find the distance and force constant of a nasal strip?
The force compulsory to be at home a nasal frame as well as request it to a nose is .25N; a appetite stored in a frame when flexed is .0022J. Assume a frame to be an preferred open for a following calculations. Find a) a stretch by that a frame is be at home as well as b) a force consistent of a strip.
This is what I’ve attempted to far: F=kx to find k, though x is not given. Why is there infrequently a disastrous pointer in front of a kx?
How do we compromise this problem? Thank we really much!
the force required to flex a spring if F=-kx the minus sign means that if you stretch the spring, the distance x increases, but the direction of the force is opposite the direction of stretching…springs always try to restore themselves to their original position…if you compress the spring (make x smaller), then the force acts in the opposite direction…hence the minus sign…back to the calculations
so here you are told that the force is 0.25N when it is flexed through a distance x…we don’t yet know x…but we know
0.25=-kx
the energy stored in a spring is
E=1/2 kx^2, and we are told the energy is 0.0022J
we have two equations in 2 unknowns, so we can solve for both x and k
from the first equation, we can write k=-0.25/x
substitute this into the energy equation:
0.0022=1/2 kx^2 =1/2(-0.25/x)x^2
or 0.0022=-0.125x=>x=-0.0176 m or 1.76cm
and we can find k:
0.25=-kx =>0.25=k(0.0176)=>k=0.25/0.0176=14.2N/m
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